Core Java · interview question
Why is left == right risky when left and right are Integer objects?
Multiple choiceHardchapter-7-curatedpremiumcore-javawrapper-types-and-autoboxing
Answer and explanation
Correct answer
B. Because == compares wrapper references, not reliable value equality
Why
With wrapper objects, == checks whether both references point to the same object, not whether the numeric values are equal. Prefer value comparison such as equals() when you mean numeric equality.
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